Variable separation - Schrödinger equation

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Discussion Overview

The discussion revolves around the application of variable separation in solving the time-independent Schrödinger equation in spherical coordinates. Participants explore the conditions under which a solution can be expressed as a product of functions, each dependent on a single coordinate.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants assert that seeking a solution in the form of Ψ(r,θ,φ) = R(r)Θ(θ)Φ(φ) is only possible if the Hamiltonian is separable in spherical coordinates.
  • Others argue that separability is not strictly dependent on symmetry, citing examples where non-symmetric potentials still allow for separable solutions.
  • One participant questions the existence of coordinate systems that would enable separability for different forms of the Schrödinger equation.
  • Another participant notes that there is no general rule for coordinate transformations that would guarantee separability, emphasizing that each case must be considered individually.
  • Examples are provided where separable solutions occur, such as in the context of a linear molecule interacting with a laser field.

Areas of Agreement / Disagreement

Participants express disagreement regarding the necessity of symmetry for separability in the Schrödinger equation. While some maintain that spherically symmetric Hamiltonians are required, others provide counterexamples suggesting that separability can occur under different conditions.

Contextual Notes

Limitations include the lack of a comprehensive method for determining suitable coordinate transformations for various forms of the Schrödinger equation, as well as the dependence on specific potential forms.

Konte
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Hello everybody,

My question is about variable separation applied in the solution of general time-independent Schrödinger equation, expressed with spherical coordinates as:

[itex]\hat{H} \psi (r,\theta,\phi) = E \psi (r,\theta,\phi)[/itex]

Is it always possible (theoretically) to seek a solution such as:

[itex]\psi (r,\theta,\phi) = R(r) . \Theta(\theta).\Phi(\phi)[/itex]

Thank you everybody.

Konte
 
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Konte said:
Is it always possible (theoretically) to seek a solution such as:

Ψ(r,θ,φ) = R(r).Θ(θ).Φ(φ)
No. It only works if the Hamiltonian is separable in spherical coordinates. It wouldn't work for example for a 3D anisotropic harmonic oscillator.
 
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DrClaude said:
No. It only works if the Hamiltonian is separable in spherical coordinates. It wouldn't work for example for a 3D anisotropic harmonic oscillator.

Thanks for your answer.

Is there a way to find or to construct a system of coordinate so that the split of Ψ is possible?

Konte
 
There is no general rule to apply what kind coordinate transform on the Cartesian Schroedinger equation in order to be separable in the new coordinate system. The coordinate transform must be sought for each form of Schroedinger equation, for example the Hamiltonian of hydrogen atom in the presence of DC electric field (Stark effect) can be transformed into parabolic coordinate to make the differential equation separable. Other form of Schroedinger equation will almost always require different transform.
 
Only if the Hamiltonian is spherically symmetric. (This generally means that the Potential is also spherically symmetric).
 
Jilang said:
Only if the Hamiltonian is spherically symmetric. (This generally means that the Potential is also spherically symmetric).
That's not true: symmetry is not necessary, only separability. If ##V(r,\theta,\phi) = \cos^2\theta##, one can still write eigenstates as ##\psi (r,\theta,\phi) = R(r) \Theta(\theta) \Phi(\phi)##.
 
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Are there many real situations like that?
 
Jilang said:
Are there many real situations like that?
Yes. The example I gave comes from the interaction of a linear molecule with a linearly-polarized laser field. You get similar potentials with (separable) angular dependence for uniform electric or magnetic fields.
 
Accepted. So generally not occurring naturally and more generally.
 

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