Sequence {(1/2)ln(1/n)} converge?

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SUMMARY

The sequence {(1/2)ln(1/n)} diverges to negative infinity. Analytical methods confirm this by demonstrating that as n approaches infinity, the limit of (1/2)ln(1/n) approaches negative infinity, which is not defined. The discussion emphasizes using the simplest test to show divergence, specifically by establishing that for any integer M, if n is less than e^M, then (1/2)ln(1/n) is less than -M, confirming the sequence's divergence.

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Homework Statement



Does the sequence {(1/2)ln(1/n)} converge or diverge?

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Working it out analytically, I think it diverges. I would like to know the appropriate test to show this

The Attempt at a Solution

 
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Seems to me that you can easily show that this diverges from the original definition. I presume that your numerical calculations (I'm not sure what you mean by "analytically". If you have show analytically that this diverges, you are done.) diverges to negative infinity.

That should lead you to look at (1/2)ln(1/n)< -M for M some large integer. Then ln(1/n)< -2M so 1/n< e-2M[/sum] and n> eM. Working the other way, for any integer M, if n< eM then (1/2)ln(1/n)< -M and so the sequence diverges.
 
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Use the simplest test.

lim n -> inf gives (1/2)ln(0) which is not defined and clearly not zero. Therefore it diverges.
 

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