Series Approximation for y with Derivative of Floor Function

Click For Summary

Discussion Overview

The discussion revolves around the series approximation for the variable y, defined as y=(1-(dx/dy)^2)^1/2, particularly when dx/dy involves the derivative of a floor function. Participants explore the implications of the floor function's discontinuity and its effects on differentiability.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Some participants question the meaning of the derivative of the floor function due to its discontinuous nature.
  • One participant suggests a series approximation for y and proposes a transformation to express dx/dy in terms of y.
  • Another participant presents an integration approach to derive x in terms of y, acknowledging the possibility of multiple valid solutions.
  • There is a discussion about the Dirac delta function and its relation to the floor function, with differing views on whether this constitutes a valid derivative.
  • Some participants argue that differentiability implies continuity, thus challenging the notion of a derivative for the floor function.
  • Others propose that distributions can be differentiated despite discontinuities, leading to further debate about the definitions and applications of derivatives in this context.
  • One participant expresses frustration with the perceived sloppiness in the application of mathematics by physicists, while another counters that the problem-solving process should not be hindered by strict definitions.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the derivative of the floor function, its applicability, and the validity of using distributions in this context. The discussion remains unresolved with no consensus on the definitions and implications of the concepts involved.

Contextual Notes

There are limitations regarding the assumptions made about the floor function and its derivative, as well as the definitions of differentiability and continuity in relation to distributions. The mathematical steps and transformations discussed are not universally accepted.

lewis198
Messages
95
Reaction score
0
I was wondering what series approximation I can use to approximate y:

y=(1-(dx/dy)^2)^1/2

when dx/dy is not trigonometric, and contains the derivative of a floor function
 
Physics news on Phys.org
Hi,
the floor function is notoriously discontinuous. What do you mean by its derivative?
 
y has properties of sin fuction i guess we solve x in terms of y

x=1/2*(abs(y)(1-y^2)^0.5 +inverse sin(abs(y)))

you can also get it solved for y
 
Last edited:
okay well an approximation
 
what do you meant by that
 
You can transform that into dx/dy = sqrt(1 - y^2) and integrate wrt y to obtain

x = -.5 {y*srt(y^2 - 1) - ln ABS(y + sqrt(y^2 -1)} + a constant

give or take a + or - :biggrin:

which does not mean the solution of sadhu is not right too.

Did this d.e. emerge from any 'real' problem?
 
Dodo said:
Hi,
the floor function is notoriously discontinuous. What do you mean by its derivative?

how about [itex]\sum_n \delta(x-n)[/itex].
 
olgranpappy said:
how about [itex]\sum_n \delta(x-n)[/itex].

I don't exactly know what you mean by that :( But I doubt that's a derivative. Differentiability implies continuity. The floor function, being discontinuous at an infinite number of points, is not differentiable.
 
That uses the delta "function". It's not a function in the true sense, but a distribution or "generalized function". And, of course, the differentiation is in the sense of distributions. Distributions do not have to be continuous in order to be differentiable. (In fact, I am not sure that "continuous" is defined for distributions!)
 
  • #10
Gib Z said:
I don't exactly know what you mean by that :( But I doubt that's a derivative.

[itex]\delta[/itex] is Dirac's delta function and the [itex]n[/itex] are positive integers. You can, of course, check for yourself that
[itex]\int_0^x dy \sum_n \delta(y-n)=Floor[y][/itex]

Differentiability implies continuity.

Lah dee dah, lah dee dah, I'm not worried about that...

The floor function, being discontinuous at an infinite number of points, is not differentiable.

But, if it's not differentiable then the derivative doesn't exist. So how did I just write the derivative down if it doesn't exist?... I'd rather not let the fact that something doesn't exist stop me from using it to solve a problem.

Mathematicians are so cute...
 
  • #11
I was never stopping you from solving the problem. Just don't call it a "derivative". Call it something else. You didn't write down the derivative, you wrote down something that satisfies a nice equation in this same manner a derivative does for continuous functions. That doesn't mean it is a derivative.

Physicists are just sloppy. There is nothing in mathematics that stops the physics being done, but physicists are too lazy to justify their mathematics. Every working physicist I have asked admits that their sloppy mathematics leads them to errors, why not correct the problem?
 
  • #12
nah.
 
  • #13
olgranpappy said:
But, if it's not differentiable then the derivative doesn't exist. So how did I just write the derivative down if it doesn't exist?
It's simple: you didn't. :rolleyes:
 
  • #14
oh, girls, stop being so silly.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K