Series Proof Help: Proving |ln 2| & |sin x|

  • Thread starter Thread starter emc92
  • Start date Start date
  • Tags Tags
    Proof Series
Click For Summary
SUMMARY

This discussion focuses on proving the error bounds for two alternating series: |ln 2 - ƩNn=1 ((-1)n-1)(1/n)| and |sin x - ƩNn=0 ((-1)n)/(2n+1)!|. The participants confirm that the error bound for alternating series can be determined using the next term in the series. Specifically, the error for the first series is bounded by 1/(N+1), while the error for the second series is bounded by |x|2N+2/(2N+2)!. Understanding these bounds is crucial for accurately estimating the convergence of these series.

PREREQUISITES
  • Understanding of alternating series and their convergence criteria
  • Familiarity with Taylor series expansions, particularly for sin x
  • Knowledge of error bounds in numerical analysis
  • Basic calculus concepts, including limits and series notation
NEXT STEPS
  • Study the properties of alternating series and their convergence
  • Learn about Taylor series and their applications in approximating functions
  • Explore error analysis techniques in numerical methods
  • Investigate the specific error bounds for various series, including ln x and sin x
USEFUL FOR

Mathematicians, students studying calculus or numerical analysis, and anyone interested in understanding the convergence and error estimation of series expansions.

emc92
Messages
33
Reaction score
0
(1) Show that |ln 2 - ƩNn=1 ((-1)n-1)(1/n)| ≤ 1/(N+1)
(2) Show that |sin x - ƩNn=0 ((-1)n)/(2n+1)!| ≤ |x|2N+2/(2N+2)!


I really don't know where to start. should I change the sums to series first then work my way through? Please help!
 
Physics news on Phys.org
Those are alternating series. The error bound is just the next element of the series.
 
ohhhhh wow now i see. thanks so much!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
14
Views
2K