Series solution for differential equation

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SUMMARY

The discussion focuses on obtaining a series solution for the differential equation x(x − 1)y" + [5x − 1]y' + 4y = 0. The original poster attempted to derive a power series solution by assuming y as a power series and differentiating it, resulting in three similar series. However, they faced challenges in combining these series into a single expression as required by the problem statement. The key takeaway is the need to compute the coefficients of x^n in the given differential equation to successfully group the series.

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  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with power series and their differentiation.
  • Knowledge of coefficient extraction techniques in series solutions.
  • Proficiency in manipulating algebraic expressions involving series.
NEXT STEPS
  • Learn about the method of Frobenius for solving differential equations.
  • Study the process of deriving coefficients in power series solutions.
  • Explore examples of series solutions for second-order differential equations.
  • Investigate the use of symbolic computation tools like Mathematica for series manipulation.
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Mathematics students, educators, and researchers focusing on differential equations, particularly those interested in series solutions and power series methods.

Sam2000009
<OP warned about not using the homework template>

Obtain a series solution of the differential equation x(x − 1)y" + [5x − 1]y' + 4y = 0Do I start by solving it normally then getting a series for the solution or assume y=power series differentiate then add up the series?

I did the latter and got three different but (slightly similar) looking series and the problem asks to group them all into one series which I cannot do
 
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Sam2000009 said:
I did the latter and got three different but (slightly similar) looking series and the problem asks to group them all into one series which I cannot do
You have a series for y, e.g. ##y = \displaystyle \sum_{n=0}^\infty c_nx^n## so that $$y' = \sum_{n=1}^\infty n c_nx^{n-1}\quad{\rm {and}}\quad y'' = \sum_{n=2}^\infty n (n-1) c_nx^{n-2} \ , $$ right ?

Now work out the coefficient of ##\ x^n ## in x(x − 1)y" + [5x − 1]y' + 4y = 0
 
Last edited:
Sam2000009 said:
The problem asks to group them all into one series which I cannot do.
What's stopping you?
 

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