1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Series Solution to Differential Equation

  1. Dec 18, 2013 #1

    ChrisVer

    User Avatar
    Gold Member

    I have to solve the differential equation
    [itex] y''+(1-t) y' + y= sin(2t)[/itex]

    can someone judge this?
    How could I continue it?

    [itex] y=\sum_{n=0}^{∞}{a_{n} t^{n}}[/itex]

    [itex] y'=\sum_{n=1}^{∞}{a_{n} n t^{n-1}}[/itex]

    [itex] y''=\sum_{n=2}^{∞}{a_{n} n(n-1) t^{n-2}}[/itex]

    [itex] sin(2t)=\sum_{n=0}^{∞}{\frac{2^{2n}}{2n!} t^{2n}}[/itex]


    [itex] y''+(1-t) y' + y= sin(2t)[/itex]
    [itex] \sum_{n=2}^{∞}{a_{n} n(n-1) t^{n-2}}+\sum_{n=1}^{∞}{a_{n} n (1-t)t^{n-1}}+\sum_{n=0}^{∞}{a_{n} t^{n}}=\sum_{n=0}^{∞}{\frac{2^{2n}}{2n!} t^{2n}}[/itex]

    [itex] \sum_{n=2}^{∞}{a_{n} n(n-1) t^{n-2}}+\sum_{n=1}^{∞}{a_{n} n t^{n-1}}-\sum_{n=1}^{∞}{a_{n} n t^{n}}+\sum_{n=0}^{∞}{a_{n} t^{n}}=\sum_{n=0}^{∞}{\frac{2^{2n}}{2n!} t^{2n}}[/itex]

    [itex] \sum_{k=0}^{∞}{a_{k+2} (k+2)(k+1) t^{k}}+\sum_{k=0}^{∞}{a_{k+1} (k+1) t^{k}}-\sum_{k=0}^{∞}{a_{k} k t^{k}}+\sum_{k=0}^{∞}{a_{k} t^{k}}=\sum_{k=0}^{∞}{\frac{2^{2k}}{2k!} t^{2k}}[/itex]

    [itex] \sum_{k=0}^{∞}{(a_{k+2} (k+2)(k+1)+a_{k+1} (k+1) -a_{k} k + a_{k}) t^{k}}=\sum_{k=0}^{∞}{\frac{2^{2k}}{2k!} t^{2k}}[/itex]

    [itex] \sum_{k=0}^{∞}{(a_{k+2} (k+2)(k+1)+a_{k+1} (k+1)+ (1-k) a_{k}) t^{k}}=\sum_{k=0}^{∞}{\frac{2^{2k}}{2k!} t^{2k}}[/itex]

    [itex] \sum_{m=0}^{∞}{(a_{2m+2} (2m+2)(2m+1)+a_{2m+1} (2m+1)+ (1-2m) a_{2m}) t^{2m}}=\sum_{m=0}^{∞}{\frac{2^{2m}}{2m!} t^{2m}}[/itex]


    [itex]a_{2m+2} (2m+2)(2m+1)+a_{2m+1} (2m+1)+ (1-2m) a_{2m}=\frac{2^{2m}}{2m!}[/itex]
     
    Last edited by a moderator: Dec 20, 2013
  2. jcsd
  3. Dec 20, 2013 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Are you sure such a series approach is useful?

    This allows to find all coefficients if you know starting values, but finding "nice" solutions based on this can be messy.
    Your series for the sin looks wrong - it has even powers of t instead of odd.
    Don't forget that you have equations both for even and odd powers of t.
     
  4. Dec 20, 2013 #3

    ChrisVer

    User Avatar
    Gold Member

    hahahaha yes, sorry about the sin, it was my mistake :p
    As for the rest, I don't know, I've seen this procedure used in so many applications (from QM, to partial derivative problems eg in cylinder or spherical coords), so I thought of applying it.... or maybe try the fourier transform of [itex]y[/itex]?
    yup I know, but because eg of the fourier transform, I could kill the (corrected) even powers
     
  5. Dec 20, 2013 #4

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    The even powers will have =0 on the right-hand side, but this is still a non-trivial equality. The derivatives mix even and odd coefficients in those equations, you cannot use symmetry as argument to ignore them.

    Power series * sin(2t) + Power series * cos(2t) could be an interesting approach. This could work with polynomials.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Series Solution to Differential Equation
Loading...