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## Homework Statement

Set bits 18, 19, 20, and 21 to 1 in register $v0. $v0's other bits should not change. This can be done in two MIPS instructions. Do not use any pseudo-instructions or load any data from memory. You may use any registers that you wish.

## Homework Equations

Here is more on the idea: if $v0 did look like this:

0b0000 0000 0000 0000 0000 0000 0000 0000 = 0x00000000

then afterwards, it should look like (counting from bit 0):

0b0000 0000 0011 1100 0000 0000 0000 0000 = 0x003C0000

Basically, just notice that bits 18 through 21 have been turned "on."

## The Attempt at a Solution

I am having trouble even coming to a possible solution in 2 steps... i know that the target is register $v0 and i have to turn 18, 19, 20, 21 into 1111 ( or F in hex) but i do not know where to start... Also i know that i maybe able to use the slt opcode ? which is set if less than to 1

any thoughts ?