Set of points equidistant from two points

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SUMMARY

The problem involves finding the equation of the set of all points equidistant from the points A(-1,5,3) and B(6,2,-2). The solution is a plane that bisects the line segment connecting points A and B. The equation of this plane can be derived using the midpoint formula and the normal vector, which is determined by the vector AB. The final equation represents all points that maintain equal distance from both A and B.

PREREQUISITES
  • Understanding of 3D coordinate geometry
  • Familiarity with the concept of a plane in three-dimensional space
  • Knowledge of vector operations, specifically vector subtraction
  • Ability to apply the midpoint formula
NEXT STEPS
  • Learn how to derive the equation of a plane given two points in 3D space
  • Study the properties of midpoints and their applications in geometry
  • Explore vector operations and their relevance in determining distances
  • Investigate the geometric interpretation of planes and their equations
USEFUL FOR

Students studying geometry, educators teaching coordinate systems, and anyone interested in understanding the relationship between points in three-dimensional space.

lat3ralus65
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Homework Statement


Find an equation of the set of all points equidistant from the points A(-1,5,3) and B(6,2,-2). Describe the set.


Homework Equations


None...


The Attempt at a Solution


Um, I've drawn a graph of the two points and that's about as far as I could get. I know the answer should be a plane going between the two points... but how do I find the equation?
 
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lat3ralus65 said:
Um, I've drawn a graph of the two points and that's about as far as I could get. I know the answer should be a plane going between the two points... but how do I find the equation?

Do you know how to write a generic equation for a plane?
 

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