Setting Up an Advanced Mathematics Equation

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The discussion revolves around solving an equation related to angle relationships, specifically finding angle θ based on the condition that twice the supplement of θ is 104 degrees greater than four times its complement. Participants emphasize the importance of correctly defining supplementary and complementary angles in algebraic terms, leading to the equations s = 180 - θ and c = 90 - θ. They work through algebraic manipulations to simplify the original equation, ultimately arriving at a solution for θ. The final answer determined through their calculations is 52 degrees. The conversation highlights the need for careful algebraic handling and understanding of angle properties.
  • #31
C=90-A
S=180-A

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  • #32
Continue :)
 
  • #33
That would make my three equations the following:
2s=4c+104 degrees=0
S=180-A
C=90-A
 
  • #34
Haha, I tried to click thanks again, and it said I gave out to much Reputation in the last 24 hours. XD
 
  • #35
So now I need to work the equations together. Am I adding like terms, or substituting the appropriate equations where I left s and c?
 
  • #36
Do whatever works best for you. Your objective is to obtain A and get rid of c and s.
 
  • #37
Okay, after plugging in my new equations, I get 2(180-A)=(90-A)+104 degrees=A
 
  • #38
If I apply the distributive property in the first part, I get (360-A)=(90-A)+104=A
 
  • #39
Can I add 104 to 90, or does that violate an algebraic rule I am forgetting?
 
  • #40
Medgirl314 said:
Okay, after plugging in my new equations, I get 2(180-A)=(90-A)+104 degrees=A

The right hand side had 4c originally.
 
  • #41
Right, thanks. So: 2(180-A)=4(90-A)+104 degrees=A ?
 
  • #42
Why do you have two equality signs there? Where does the second one come from?
 
  • #43
I was attempting to state that those two equations are equal to both each other and A. Is the =A not supposed to be there?
 
  • #44
The original equation was 2s = 4c + 104. You substituted s = 180 - A and c = 90 - A into it. How would that bring about = A to it?
 
  • #45
No idea. It snuck it's way in there. So: 2(189-A)=4(90-A)+104 degrees.
 
  • #46
Shall I apply the distributive property?
 
  • #47
I hope 189 was a typo.

Your goal to is to transform the equation to A = ..., where the right hand side does not have A. Use whatever algebraic rules that help you achieve that. It is not too hard.
 
  • #48
Major typo. It was meant to be 180. The nine is, of course, right next to the zero, and I was typing too quickly.
 
  • #49
Applying distributive property: (360-A)=(360-A)+104.
Combining like terms: (720-2A)+104

Why doesn't that seem right?
 
  • #50
Probably because I eliminated the equal sign...
 
  • #51
Not only that, you did not apply the distr. property to A's.
 
  • #52
Right! Take five-billion: (360-2A)=(360-4A)
That should look better.
 
  • #53
Wait, nope. It doesn't make sense.
 
  • #54
I forgot the 104. Maybe this will work. (360-2A)=(360-4A)+104
 
  • #55
This is better :)
 
  • #56
Finally. It astonishes me that I had less trouble with Honors Physics the other day than with basic algebra.
(360-2A)=(464-2A)
 
  • #57
Oops. (360-2A)=(464-4A)
 
  • #58
Doesn't seem right. Should I subtract the 104 instead of adding?
 
  • #59
But that would yield (360-2A)=(256-4A), which also seems wrong.
 
  • #60
Oh! I forgot P.E.M.D.A.S.
 

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