Setting up an integral for surface area

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To find the surface area generated by rotating the region bounded by x + y² = 1 and the y-axis about the y-axis, the integral must be set up correctly. The surface area formula SA = 2π ∫ x ds is relevant, where ds represents the differential arc length. A proposed integral is 4π ∫ (-y² + 1)√(1 + 4y²) dy, with limits from 0 to 1, which reflects the correct approach to the problem. The discussion highlights the challenge of visualizing the surface area and correctly applying the formula. Understanding the relationship between the variables and the geometry involved is crucial for setting up the integral accurately.
Abyssnight
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Homework Statement


Set up an integral that represents the area of the surface generated when the region is bounded by x + y2 = 1 and the y-axis, then rotated about the y-axis. All in one-variable.


Homework Equations


SA = 2pi \int xds
possible x2 + y2 = r2

The Attempt at a Solution


I tried to set up an integral as a circle and somehow ended up getting 2pi\int(r/2)(2pi r) dr

When I picture it, it would be a sphere with a radius of 1. Still don't truly understand on how to make a integral to show it
 
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I looked at it again
would one possible answer be: 4pi\int(-y^2 + 1)\sqrt{1 + 4y^2}dy
with limits of integration (0,1)
 
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