Setting Up Triple Integral for Region Bounded by x=y^2, z=0, x+z=1

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SUMMARY

The discussion focuses on setting up a triple integral for the region bounded by the equations x=y², z=0, and x+z=1. The correct limits for the integrals are established as follows: the dz integral ranges from z=0 to z=1-x, the dy integral spans from y=-√x to y=√x, and the x integral is defined from 0 to 1. A visual representation of the region is recommended for better understanding of the integration limits.

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stratusfactio
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Homework Statement


Set up the triple integral for the region bounded by:

x=y^2, z=0, x+z=1

Homework Equations


The Attempt at a Solution


y= ±sqrt(x); z=0 & z=x+1
I'm just lost on how to find the x integral. I know the dz integral goes from z=0 to z=x+1, and I know the dy integral goes from y=-sqrt{x} to +sqrt{x}. I also know if we set 0=x+1, we get x=1, but how do I find the remaining limit of integration?
 
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Hi stratusfactio! :smile:

Your maximum z is a little off, it should be 1-x.

As for x, what's wrong with 0 to 1?
(I suggest you try to make a drawing.)
 

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