Shouldn't Emf generated be Derivative of Flux?

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SUMMARY

The discussion clarifies that the electromotive force (emf) generated in a circuit is indeed the negative derivative of magnetic flux with respect to time, as expressed by the formula E = -dΦ/dt. The confusion arises from the misconception that emf is the first derivative of flux; however, it is essential to include the negative sign due to Lenz's law, which accounts for the direction of induced emf. The example provided illustrates this with a sine function representing magnetic flux, where the derivative yields a cosine function, confirming the relationship between flux and emf.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with calculus, specifically derivatives
  • Knowledge of Lenz's law and its implications
  • Basic grasp of magnetic flux concepts
NEXT STEPS
  • Study the implications of Lenz's law in electromagnetic systems
  • Explore the mathematical derivation of Faraday's law of induction
  • Learn about applications of emf in electrical circuits
  • Investigate the relationship between magnetic fields and induced currents
USEFUL FOR

Physics students, electrical engineers, and anyone studying electromagnetic theory will benefit from this discussion, particularly those interested in the principles of induction and the mathematical relationships governing emf and magnetic flux.

Ashman Kumar
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Hey, I don't understand why emf generated is not the first derivative. For example I have a graph of magnetic flux through a wire against time. I thought that emf generated was the rate of change of flux, however this doesn't work. Emf=-Dflux/Dtime . In this example I have a y=sinx curve for the magnetic flux through wire and the answer is y=-cosx, which is the integral. Thanks in advance
 

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It's not the integral, its the negative (!) derivative with respect to time. You even posted the correct formula already. $$E = - \frac{d\,\Phi}{d\,t}$$ You need the minus sign due to Lenz's law.
 
That was actually quite simple, thanks for your explanation
 
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