Show 'a' is Irreducible: If R a Max Ideal in R

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In the discussion, it is established that if 'a' is an element of a commutative ring R and the principal ideal Ra is a maximal ideal, then 'a' must be an irreducible element. The reasoning follows that if 'a' were reducible, expressed as a product 'a = bc' for some elements b and c in R, one of these must be a unit to prevent the existence of a larger ideal than (a). The discussion emphasizes that maximal ideals are inherently prime ideals, reinforcing the conclusion about the irreducibility of 'a'.

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mansi
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Here’s an interesting question…
Let R be a commutative ring and ‘a’ an element in R. If the principal ideal Ra is a maximal ideal of R then show that ‘a’ is an irreducible element.
If a is prime, this is pretty obvious…if a is not prime, then we say a= bc for some b,c in R. Now we need to show that either of them is a unit. I can’t imagine how… :frown:
 
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If a is reducible, try finding a bigger ideal than (a). Maximal ideals are always prime ideals!
 
the usual definition of a prime element in a commutative ring with identity, is that it generates a prime ideal.
 

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