Show ##(\frac{\partial S}{\partial G})_Y = -\frac{C_Y}{TS}##

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SUMMARY

The discussion focuses on demonstrating the equation ##(\frac{\partial S}{\partial G})_Y = -\frac{C_Y}{TS}##, where ##G## represents Gibbs free energy, ##H## is enthalpy, and ##C_Y## is the heat capacity at constant Y. The relationship is derived from the fundamental thermodynamic equation ##dG = dH - TdS - SdT##, utilizing the definition of heat capacity as ##C_Y = (\frac{\partial H}{\partial T})_Y##. The confusion arises regarding the variable Y, which may be intended to represent volume (V) instead.

PREREQUISITES
  • Understanding of thermodynamic concepts, specifically Gibbs free energy and enthalpy.
  • Familiarity with partial derivatives in thermodynamics.
  • Knowledge of heat capacity definitions and their applications.
  • Basic grasp of state variables in thermodynamic equations.
NEXT STEPS
  • Review the derivation of Gibbs free energy and its relation to enthalpy and entropy.
  • Study the implications of heat capacity at constant volume and pressure.
  • Explore the use of partial derivatives in thermodynamic equations.
  • Investigate the significance of state variables in thermodynamic systems.
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This discussion is beneficial for students and professionals in thermodynamics, particularly those studying physical chemistry or engineering, as well as anyone seeking to deepen their understanding of Gibbs free energy and its derivatives.

GL_Black_Hole
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Homework Statement


Show that ##(\frac{\partial S}{\partial G})_Y = -\frac{C_Y}{TS}##

Homework Equations


##G = H-TS, (\frac{\partial H}{\partial T})_Y = C_Y##

The Attempt at a Solution


##dG = dH -TdS -SdT## and ##H## is a state variable so ## dH =\frac{\partial H}{\partial T} dT + \frac{\partial H}{\partial Y} dY##. Not sure how to use the given information or continue from here.
 
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What you have written makes little sense. I do think the ## Y ## my actually be a ## V ##, but to take the partial derivative of ## S ## w.r.t. ## G ## is also rather odd.
 

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