Show if its a lin. independent subset

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SUMMARY

The discussion centers on determining the linear independence of the subset S = { (0,1,1,1,0) } within the vector space V defined by the equation x_{1} - 2x_{2} + 3x_{3} - x_{4} + 2x_{5} = 0. It is established that a set containing a single non-zero vector is inherently linearly independent. The key step is to verify that the vector (0,1,1,1,0) satisfies the equation defining V, confirming that S is indeed a subset of V.

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Homework Statement



V = { (x_{1},x_{2},x_{3},x_{4},x_{5}) \in R^{5} : x_{1} -2x_{2} + 3x_{3} - x_{4} + 2x_{5} = 0 }

show that S = { (0,1,1,1,0) } is a linearly independent subset of V.

The Attempt at a Solution



I don't get it.. it's a set with 1 non zero vector, it's going to be linearly independent? then do I just have to show that it's actualy in V?

thanks
 
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Yes, a set with 1 element is going to be linearly independent. You must verify that (0,1,1,1,0) is actually in V to show that S is a subset of V. Just plug the vector into the equation and see if you get 0.
 
thanks, I thought I was misunderstanding something.. since it looked to trivial to me haha
 

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