oahz Messages 13 Reaction score 0 Thread starter May 28, 2014 #1 Please, hurry. It's driving me nuts Attachments image.jpg 38 KB · Views: 468
economicsnerd Messages 268 Reaction score 24 May 28, 2014 #2 I suppose ##f \geq 0##? If so, ##y\geq x \implies yf(y) \geq xf(y)##.
Nick O Messages 158 Reaction score 8 May 28, 2014 #3 Seconded. Note that y takes on every value >= x, so you have basically replaced the constant x with the increasing function y in the integral.
Seconded. Note that y takes on every value >= x, so you have basically replaced the constant x with the increasing function y in the integral.