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**1. Homework Statement**

[tex]\Sigma\frac{sin(n)}{n}[/tex]

from n=1 to infinity

i have to show that this series converges, but that it doesnt converge absolutely.

**2. Homework Equations**

the thing is, I figured th

**3. The Attempt at a Solution**

if you say that the top of the equation is -1<sin(n)<1, you can then take the absolute value to get 0<sin(n)<1. so then the equation can look like this:

[tex]\Sigma\frac{1}{n}[/tex] from n=1 to infinity, which is a divergent series. i just dont know how to show that the original equation is convergent.