1. The problem statement, all variables and given/known data Letting the line be x=0 , y = t and z = t Show that the line is parallel to and below the plane 5x - 3y + 3z = 1 3. The attempt at a solution - First I assigned t = 1 and t = 4 to obtain two points of the line: P1 = (0,1,1) and P2 = (0,4,4) - Then I created a directional vector P1P2 = (0-0, 4-1 , 4-1) = (0,3,3) - We know that n = (5, -3, 3) - So if we prove that n and P1P2 are orthogonal (i.e.their dot product is 0), then THE PLANE AND LINE ARE PARALLEL. Please tell me if I made any mistake so far... - But how do you prove the line is BELOW the plane??? Thanks!