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Show that for any square matrix, the matrix A +(A)^t is sym

  1. Jan 30, 2015 #1
    Show that for any square matrix, the matrix A + ( A )^t is symmetric.

    My attempt. I know that A square matrix has the property that asub (ij). Where i=1,..., m and j=1,..,n.
    M=n(same number of rows and columns).

    I know that a transpose of a matrix means to interchange the rows with columns.

    What I do not understand what it means for a matrix to be symmetric?
  2. jcsd
  3. Jan 30, 2015 #2
    Sorry I forgot the t means the transpose if anyone is confused about my notation.
  4. Jan 30, 2015 #3


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    A matrix B is symmetric if BT=B

    In other words Bmn=Bnm for all entries (which also means it must be square). The diagonal entries can be anything because, for example, B11=B11 is always true. But B12 must equal B21, and so on.

    (It's easy to understand visually.)
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