Show that Q is proportional to V for capacitor

Click For Summary

Homework Help Overview

The discussion revolves around demonstrating experimentally that the charge stored on a capacitor is proportional to the potential difference across it. The specific context involves a 220 µF capacitor and potential differences ranging from 0 to 15 V.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster outlines a method involving charging the capacitor and measuring the charge using the relationship Q=It, while questioning the effectiveness of their approach. Some participants inquire about methods to measure charge and express concerns about maintaining a constant current during the charging process.

Discussion Status

The discussion is ongoing, with participants exploring the feasibility of the proposed method and raising questions about measurement techniques. Some guidance has been offered regarding the challenges of maintaining constant current, but no consensus has been reached.

Contextual Notes

Participants note that the original poster's syllabus mentions coulombmeters, but there are concerns about their adequacy for the experiment due to the high capacitance involved.

jsmith613
Messages
609
Reaction score
0

Homework Statement


Describe how you would show experimentally that the charge stored on a 220 µF capacitor is proportional to the potential difference across the capacitor for a range of potential differences between 0 and 15 V. Your answer should include a circuit diagram.


Homework Equations





The Attempt at a Solution



attachment.php?attachmentid=152384&d=1338318521.png


- charge the capacitor for a given Voltage, V
- ensure the capacitor is charging at a constant rate by varying the resistance of the variable resistor --> ensures current remains constant
- Q=It (current * time take for capacitor to charge)
- capacitor is charged when V on meter = V of supply
- Q/V = constant for range of values of V

Is this method correct - would it work?

p.s: I am aware my diagram is not very well drawn - i will obviously improve this in the exam
 
Physics news on Phys.org
V is easy to measure...do you know of any way to measure Q?
 
truesearch said:
V is easy to measure...do you know of any way to measure Q?

my syllabus only talks about coloumbmeters but the MS said the a coloumbeter would be insufficient for this experiment because the capacitance is too high.

I was simply wondering, would my method work?
 
Your method sounds good to me - although it might be a bit tricky keeping the current constant unless the capacitor was charging very slowly.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K