Show that the eigenvalues of the overlap matrix are positive

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SUMMARY

The eigenvalues of the overlap matrix \(\tilde S\) are confirmed to be positive, as demonstrated through the positive definiteness of the matrix. The overlap matrix is defined as \((\tilde S)_{nm} = \langle \xi_n \vert \xi_m \rangle\), where \(\xi_k\) represents the base vectors of the wavefunction. The proof involves verifying that \(\vec x^{\ast} \tilde S \vec x > 0\) and ensuring all sub-determinants are greater than zero. Additionally, the diagonal elements are inherently positive, reinforcing the conclusion.

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  • Knowledge of quantum mechanics and wavefunction representation
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  • Learn about the derivation and applications of the overlap matrix in quantum systems
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jarra
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Homework Statement


The task is to show that the eigenvalues of overlap matrix [tex]\tilde S[/tex] are positive.


Homework Equations


The overlap matrix is defined as [tex](\tilde S)_{nm} = \langle \xi_n \vert \xi_m \rangle[/tex], with [tex]\xi_k[/tex] being the base vectors of the wavefunction. http://en.wikipedia.org/wiki/Overlap_matrix


The Attempt at a Solution


I've tried to show that the eigenvalues are positive by showing that [tex]\tilde S[/tex] is positive definite. Both with the condition [tex]\vec x^{\ast} \tilde S \vec x > 0[/tex] and the condition that all the 'sub-determinants' are larger than zero. But I don't get it right, please help.
 
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jarra said:

Homework Statement


The task is to show that the eigenvalues of overlap matrix [tex]\tilde S[/tex] are positive.


Homework Equations


The overlap matrix is defined as [tex](\tilde S)_{nm} = \langle \xi_n \vert \xi_m \rangle[/tex], with [tex]\xi_k[/tex] being the base vectors of the wavefunction. http://en.wikipedia.org/wiki/Overlap_matrix


The Attempt at a Solution


I've tried to show that the eigenvalues are positive by showing that [tex]\tilde S[/tex] is positive definite. Both with the condition [tex]\vec x^{\ast} \tilde S \vec x > 0[/tex] and the condition that all the 'sub-determinants' are larger than zero. But I don't get it right, please help.

In a naively way i would say: It is just an integral of a probability distribution---> it is positive by definition!

More thecnically: the diagonal members are for sure positive and what about the off diagonal?

Hint: use the fact that [tex]S_{jk}=\overline{S}_{kj}[/tex]
 

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