1. Show that the series is convergent and then find how many terms we need to add in order to find the sum with an error less than .001 Ʃ (-1)(n-1)/ √(n+3) from n = 1---> infinity 2. I took the derivative. 3. f(x) = (x+3)-1/2 f'(x) = -1/2 (x+3)-3/2 Then I set up the following Absolute value (1/(n+1+3)) < .001 n+4 > (1/.001)2 Got 999,997 for the answer. not sure what Im doing wrong. Help!