Show that Vector function lies on a sphere

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To show that a differentiable 3-space vector-valued function r lies on a sphere centered at the origin, it is necessary to demonstrate that r(t) and r′(t) are orthogonal for all t. The condition ||r(t)|| = C indicates that the magnitude of r(t) is constant, implying that the function traces a spherical surface. Differentiating the equation r(t) · r(t) = C^2 leads to the conclusion that the derivative r′(t) must be perpendicular to r(t). The proof requires addressing both the necessary and sufficient conditions due to the "if and only if" nature of the statement. Thus, the relationship between r(t) and r′(t) is crucial for establishing the sphere's property.
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Homework Statement



Let r1 and r2 be differentiable 3-space vector-valued functions.

Show that for a differentiable 3-space vector-valued function r, the graph of r lies on a sphere centered at the origin if and only if r(t) and r′(t) are orthogonal (perpendicular) for all t.

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The Attempt at a Solution


If R(t) is on the surface of such a sphere then ||R(t)||=C, is constant.
 
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so, if i;m interpreting this correctly if ||r(t)||=c, then you could write it as:

\textbf{r}(t) \bullet \textbf{r}(t) = c^2
how about differentiating...

note that as the question has "if & only if" you must show both directions, necessary & sufficient" to complete the proof
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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