Show the set S is a subspace of Real Numbers^3

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SUMMARY

The set S = {(x, y, z) | x + 2y − z = 0} is confirmed as a subspace of Real Numbers^3. To establish this, it is essential to demonstrate closure under addition and scalar multiplication. Specifically, if (x1, y1, z1) and (x2, y2, z2) are elements of S, their sum (x1 + x2, y1 + y2, z1 + z2) must also satisfy the equation x + 2y − z = 0. Additionally, for any scalar c, the product c(x, y, z) must remain in S, fulfilling the same equation.

PREREQUISITES
  • Understanding of vector spaces and subspaces
  • Familiarity with linear equations and their geometric interpretations
  • Knowledge of closure properties in vector spaces
  • Basic proficiency in Real Numbers^3
NEXT STEPS
  • Study the properties of vector spaces, focusing on closure under addition and scalar multiplication
  • Explore examples of subspaces in Real Numbers^n
  • Learn about linear independence and spanning sets
  • Investigate the implications of the zero vector in subspaces
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Students studying linear algebra, mathematicians exploring vector spaces, and educators teaching concepts related to subspaces in Real Numbers.

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Homework Statement



Show that set S = {(x , y, z ) | x + 2y − z = 0} is a subspace of Real Numbers^3.


Homework Equations



A subspace needs to be closed under addition and scalar multiplication

The Attempt at a Solution



S = { (x, y, x+2y) | x, y are elements of Real Numbers }

Now where do I go from here what do I have to do to show closure under addition and scalar multiplication ?


Thanks !
 
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Just use the definitions:

Show that if you have two elements in S that their sum is in S.

Show if you have an element in S that a constant times it is in S.
 

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