MHB Show the trigonometric equation has no solutions

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The trigonometric equation $\sin (\cos a) = \cos (\sin a)$ is examined for potential solutions. It is established that the range of $\sin(\cos a)$ is limited to the interval [-1, 1], while $\cos(\sin a)$ also falls within the same range. However, through analysis, it is demonstrated that these two functions do not intersect at any point within their respective ranges. Consequently, it is concluded that the equation has no solutions. The proof relies on the properties and behaviors of the sine and cosine functions.
anemone
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Show that the trigonometric equation $\sin (\cos a)= \cos (\sin a)$ has no solutions.
 
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anemone said:
Show that the trigonometric equation $\sin (\cos a)= \cos (\sin a)$ has no solutions.

if sin (x) = cos (y) then

$x+y = \pi/2 +2npi$ or $(2n+1)pi-\pi/2$

so lowest | cos a + sin a | = $\pi/2$

so |cos a + sin a| =$ \pi/2$ should have a solution

but |cos a + sin a | <= $\sqrt(2)$

so no solution
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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