Showing a metric space is complete

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SUMMARY

The discussion focuses on proving that the space of all continuous real-valued functions on the interval [0, a], equipped with the metric d(x,y) = sup_{0≤t≤a} e^{-Lt}|x(t) - y(t)|, is a complete metric space. The key approach involves demonstrating that every Cauchy sequence of functions converges to a limit within the space. The solution requires showing pointwise convergence of the sequence (x_n(t))_n to a function x(t) and establishing the continuity of x, along with the convergence in the specified metric.

PREREQUISITES
  • Understanding of Cauchy sequences in metric spaces
  • Familiarity with the concept of continuity for functions
  • Knowledge of supremum metrics and their properties
  • Basic principles of real analysis
NEXT STEPS
  • Study the properties of Cauchy sequences in metric spaces
  • Learn about pointwise and uniform convergence of functions
  • Explore the definition and implications of complete metric spaces
  • Investigate the role of exponential decay in metrics
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Mathematics students, particularly those studying real analysis, and researchers interested in functional analysis and metric space theory.

chipotleaway
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Homework Statement


Show the space of all space of all continuous real-valued functions on the interval [0, a] with the metric d(x,y)=sup_{0\leq t\leq a}e^{-Lt}|x(t)-y(t)| is a complete metric space.

The Attempt at a Solution


Spent a few hours just thinking about this question, trying to prove it directly from the definition that says a complete metric space is one where every Cauchy sequence in it has a limit in the space.

I started with an arbitrary Cauchy sequence of functions d(x_m, x_n)=sup_{0\leq t\leq a}e^{-Lt}|x_m(t)-x_n(t)|...that's it! I don't know how to find this limit and show that the sequence converges to that.
 
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Try to show that your sequence converges pointswise. So show that for every ##t##, the sequence ##(x_n(t))_n## converges to some real number which I denote by ##x(t)##. Then show that ##x## defined like this is continuous and that ##x_n\rightarrow x## in your metric.
 

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