Showing S1+S2 is Dense in Hilbert Space

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Homework Help Overview

The discussion revolves around the properties of two subspaces, S1 and S2, within a Hilbert space defined by an orthonormal basis. The original poster aims to demonstrate that the sum of these subspaces, S1 + S2, is dense in the Hilbert space and to evaluate the density and closedness of S2.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster considers the closure of S1 + S2 in relation to the orthonormal basis. There is a question about whether an undense set combined with a dense set can result in a dense set. Participants discuss the inclusion of specific basis elements in S1 + S2 and explore the implications for the density and closedness of S2.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the relationships between the elements of S1 and S2. There is a recognition of the need for further exploration regarding the properties of S2, with some participants expressing tentative agreement on the conclusions drawn about its density and closedness.

Contextual Notes

There is an ongoing examination of the definitions of dense and closed sets, as well as the implications of the specific vectors involved in the subspaces. The original poster indicates familiarity with these concepts but is seeking clarification on their application in this context.

Raven2816
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Homework Statement


i have {ej} is an orthonormal basis on a hilbert space
S1 is the 1-dimensional space of e1 and
S2 is the span of vectors ej + 2e(j+1)

eventually i need to show that S1 + S2 is dense in H and also evaluate
S2 for density and closedness

Homework Equations



i know the def. of closed, dense, spans, etc...

The Attempt at a Solution



well, i know that i need to show that S1+S2 is dense by showing that its closure = my orthornormal basis. i think S2 is closed but not dense, but can an undense set + a dense set be a dense set?
 
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e1 is in S1 and 0 is in S2, so e1 = e1 + 0 is in S1 + S2.
Is e2 in S1 + S2?
 
yes...e2 = e1 + e1 + 0?
 
Raven2816 said:
yes...e2 = e1 + e1 + 0?
No, e1 + e1 is not e2. But (e1 + e2) - e1 is e2.
 
then S2 is dense afterall, but not closed. ...at least from what I've worked out since.
 
Raven2816 said:
then S2 is dense afterall, but not closed. ...at least from what I've worked out since.
I haven't looked at this carefully, but my first impression is that you are correct. Do you need further help with this?
 

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