Showing that the gradient of a scalar field is a covariant vector

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Homework Help Overview

The discussion revolves around proving that the covariant gradient of a scalar field transforms as a covariant vector in a general coordinate system. Participants are exploring the mathematical properties of the covariant gradient and its transformation under a change of basis.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to show that the covariant gradient transforms as a 1-covariant tensor, questioning their reasoning regarding the transformation properties of the involved tensors.
  • Some participants suggest using familiar notation and transformation rules to express the components of the covariant gradient in terms of the transition matrix, aiming to derive the necessary transformation properties.
  • There is a discussion about the relationship between the components of the transition matrix and the derivatives involved in the transformation.

Discussion Status

The discussion is ongoing, with participants providing insights and suggestions for approaching the proof. There is an acknowledgment that the demonstration may be simpler than initially thought, but clarity is still sought regarding the transformation properties.

Contextual Notes

Participants are working within the constraints of a homework assignment that requires a proof of the transformation properties of the covariant gradient. There is an emphasis on understanding the underlying mathematical concepts rather than simply arriving at a solution.

AndersF
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Homework Statement
Prove that the covariant gradient of a scalar field is a covariant vector
Relevant Equations
##\nabla f=\frac{\partial f}{\partial x^{i}} g^{i j} \mathbf{e}_{j}##
In a general coordinate system ##\{x^1,..., x^n\}##, the Covariant Gradient of a scalar field ##f:\mathbb{R}^n \rightarrow \mathbb{R}## is given by (using Einstein's notation)

##
\nabla f=\frac{\partial f}{\partial x^{i}} g^{i j} \mathbf{e}_{j}
##

I'm trying to prove that this covariant gradient ##\nabla f## is indeed a covariant vector. To do so, I'm trying to show that it transforms as a 1-covariant tensor under a change of basis.

Let ##C## be the transition matrix from a basis ##\{\mathbf e_i\}## to a basis ##\{\tilde {\mathbf e}_i\}##, that is, ##\tilde {\mathbf e}_i= \mathbf e_iC^i_j##.

The covariant derivative increases the contravariant tensor order of the tensor by one unit. Since the partial derivative of a scalar field is indeed a covariant derivative, the object ##\frac{\partial f}{\partial x^{i}}## will therefore be a 1-covariant tensor which I will call ##F_i##.

On the other hand, the contraction between the dual metric tensor ##g^{ij}## and ##F_i## will raise the subscript ##i## of ##F_i##, and the resulting object will be a 1-contravariant tensor: ##g^{ij}F_i\equiv H^j##.

But then, ##\frac{\partial f}{\partial x^{i}} g^{i j}=H^j## will transform as the contravariant components of a contravariant vector ##\mathbf{v}=H^j\mathbf{e}_{j}##: ##\tilde H^j=(C^{-1})^j_kH^k##, which is just the opposite of what I have to prove...

Where is my mistake? How could this be proved?
 
Last edited:
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I don't recognise your notation. I'm more familiar with things like:
$$g^{ij} = g^{k'l'}\frac{\partial x^i}{\partial x^{k'}}\frac{\partial x^j}{\partial x^{l'}}$$If you do the same for the basis vector and partial derivatives, you can express the components of ##\nabla' f## in terms of the components of ##\nabla f## and derive/confirm the relevant transformation rule.
 
PS the result should drop out in a couple of lines.
 
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PeroK said:
PS the result should drop out in a couple of lines.
I too think that the demonstration should be shorter than what I have tried, but I don't find the problem...

By the way, the components of the transition matrix ##(C^i_j)## of my notation are the terms ## \frac{\partial x^i}{\partial x'^j}## of your notation, aren't they?
 
AndersF said:
I too think that the demonstration should be shorter than what I have tried, but I don't find the problem...
If I understood what you were doing, I'd try to help!
 
AndersF said:
Homework Statement:: Prove that the covariant gradient of a scalar field is a covariant vector
Examine the chain rule: ##\partial / \partial x^j = (\partial x'^i/\partial x^j) \partial / \partial x'^i##. The Jacobian ##\partial x'^i/\partial x^j## is your transition matrix.
 

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