Signal Analysis - Invertibility

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The discussion centers on the invertibility of the system defined by y(t) = cos(x(t)). The confusion arises from the assumption that applying arccos to y(t) would yield x(t), suggesting the system is invertible. However, the system fails to be invertible because multiple values of x(t) can produce the same y(t), as demonstrated with different inputs T1 and T2 yielding the same output. The key point is that for y(t) = 1, there are multiple corresponding values of t, indicating a lack of unique mapping. Thus, the system is not invertible according to the definition provided in the book.
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I don't understand why my book is saying that this system is not invertible.

y(t) = cos(x(t))

?

Wouldn't, arccos{ y(t) } = x(t) and therefore be an inverse system?
 
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First check on what your book says the definition of invertible is.

What about times T1 and T2, where T1 and T2 are different

x(T1) = 0, x(T2)= 2PI

y(T1) = 1 and y(T2)=1

Suppose

y(t)=1 what is the value of t?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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