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Signal, noise, and, unequal variances

  1. Apr 13, 2008 #1

    Math Is Hard

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    I have two overlapping Gaussian distributions. One for probability of a noise event, one for probability of a signal event.
    My noise distribution has mean = 0, variance = 1, and standard deviation = 1.
    My signal distribution has mean = .80, variance = 3, and standard deviation = √3.

    My criterion (λ ) is at 0.5 standard deviations above the mean on the noise distribution.

    I need to calculate probability of a hit (PH) and probability of a false alarm (PF).

    To get PF , I use 1- PCorrect Rejection, or 1 – Ф(0.5), which, using a Z to % conversion table, gives me 1- 0.691 = 0.31. (In my book, Ф(Z) just means converting a Z-score to % of area under the curve.)

    To get PH, I first need to standardize the Z score for λ on the signal distribution since it has a different variance:

    λ = (λ - μsignal)/σ signal = (0.5-0.8) / √3 = - 0.173

    PH = 1 - Ф(-0.173) or by symmetry, PH = Ф(0.173) = 0.57. (again, using a Z to % conversion table to look up the area.)

    So.. PF = = 0.31 and PH = 0.57.

    I'm not sure if I did this right. I am shaky with unequal variances. If someone could check I'd appreciate it.

    I need to sketch the overlapping distributions. Since I have standardized the z-score on the signal distribution, do I make it look identical to the noise curve (with a standard deviation of 1), or do I draw it short and wide as it is originally described?

    Thanks!
     
  2. jcsd
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