How does one find sample size without a given variance?

[Eclair_de_XII]

Homework Statement

"The mean pH value of a certain chemical is to be controlled at $\mu = 5$. Deviation from this target value in either direction is to be detected with high probability. For this purpose it is proposed to measure a ceratin number of samples from each batch and decide that the mean pH is different from 5 if the sample mean differs significantly from 5 at the 10% level of significance."
(b) "What sample size is needed if the probability of not detecting a change of one standard deviation is to be no more than 1%?"

Homework Equations

$H_0: \mu = 5$
$H_1: \mu ≠ 5$

The Attempt at a Solution

Basically, I'm interpreting this probability as the probability of a type-II error. So $\beta = 0.01$. I know that the formula for the required sample size in this case would be: $n=(\frac{\sigma}{E})^2$, but I don't know what $\sigma$ is. For that matter, I don't know what $E$ is supposed to be, either. So I'm kind of stuck, here.

 

[mjc123]

What is the relationship between the variance of a sample and the variance of the mean?

 

[Stephen Tashi]

The question , as quoted, has a part (b). Is there a part (a)?

 

[Eclair_de_XII]

What is the relationship between the variance of a sample and the variance of the mean?

Let's see... The variance of a sample is: $s^2=\frac{1}{n-1}∑(\bar X - X_i)^2$ and the variance of the mean, was $Var(\bar X)=\frac{Var(X)}{\sqrt{n}}$? I'll get back to you on the matter of their relationship.

Is there a part (a)?

(a) "State the null hypothesis and the alternate hypothesis. What can you infer about the statistic $\mu$?"
I didn't think it was related to the problem, so I decided to exclude it.

 

[Stephen Tashi]

but I don't know what $\sigma$ is.

Instead of thinking about a statistic ("z") with a normal distribution, think about using the statistic with a t-distribution.

 

[Eclair_de_XII]

So what I'm gathering is to find an $n$ such that $T=\frac{\mu - \bar x}{s/\sqrt{n}}=t_{n-1,\alpha /2}$.

In any case, though, my instructor told me to use $-z_{\alpha /2}+\frac{\delta \sqrt{n}}{\sigma}=z_{\beta}$, and by setting $\delta=\sigma$, I get $n=(z_{\alpha /2}+z_{\beta})^2$.