Significance of the second derivative

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SUMMARY

The discussion centers on the interpretation of the second derivative in the context of a mathematical model representing the number of students contracting measles over time, denoted as y = s(t). Specifically, when the first derivative s' equals zero and the second derivative s" is greater than zero, it indicates that while the rate of new infections has stopped (s' = 0), the acceleration of the infection rate is increasing (s" > 0). This means that the number of infections is stabilizing at a maximum point, but the potential for future increases is present as the conditions change.

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SithsNGiggles
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Homework Statement



Let y = s(t) represent the number of students who have contracted measles at time t (days). Give an interpretation for each condition:

e) s' = 0, s" > 0

The Attempt at a Solution



This seems counterintuitive to me, to think that the second derivative is also not zero. In the context of the problem, what does this mean? So far I've said that no students are contracting measles anymore, but I don't know where s" fits in here.
 
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well for a start what does s'=0 tells you about the problem?

its not counter-intuitive to have s" non-zero whilst s'=0. If s" is non-zero it simply means the value of s' is changing

HINT: if you know s'=0, and s" is non zero, then s' must be changing from either (+ve to -ve) or (-ve to +ve)
 

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