Simple algebraic / logarithmic question

  • Thread starter Thread starter mofoj
  • Start date Start date
  • Tags Tags
    Logarithmic
Click For Summary

Homework Help Overview

The discussion revolves around solving the equation (1.024)^2 = (1 + m)^12, focusing on the algebraic manipulation and logarithmic properties involved in isolating the variable m.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore methods such as taking the 12th root and using logarithms to simplify the equation. There are questions about the correctness of the operations performed, particularly regarding the distinction between raising to a power and taking a root.

Discussion Status

Several participants have provided guidance on the steps to take, with some clarifying the difference between raising to a power and taking a root. There is an ongoing exploration of the correct approach to isolate m, with various interpretations being discussed.

Contextual Notes

Some participants express uncertainty about their previous knowledge and the methods they learned, indicating a potential gap in understanding the algebraic principles involved.

mofoj
Messages
5
Reaction score
0

Homework Statement



(1.024)^2 = (1 + m)^12

Homework Equations





The Attempt at a Solution



1.048576 = (1+m)^12
I tried to do a square root of 12 for both sides but does not appear to be correct. I've also tried doing log to bring the exponents to the front for both sides, but something is wrong. I learned this long time ago so I really can't remember how to approach it.
 
Physics news on Phys.org
I guess you are trying to solve for m?

Starting with a 12th root of both sides seems like a reasonable way of dealing with the exponent.
 
Borek said:
I guess you are trying to solve for m?

Starting with a 12th root of both sides seems like a reasonable way of dealing with the exponent.


Yeah that's what I did, but I did not get the correct answer, which should be 0.003961.
 
What did you get when you took the 12th root of 1.048576? And did you subtract 1 from both sides after taking the 12th root?
 
eumyang said:
What did you get when you took the 12th root of 1.048576? And did you subtract 1 from both sides after taking the 12th root?

yes I did subtract the 1 after, but it is not the correct answer still.
 
Mark44 said:
Show us what you did...

1.048576 = (1+m)^12

12th sq root
10.69516372 = 1 + m
9.69516372 = m


supposed to be 0.003961
 
mofoj said:
1.048576 = (1+m)^12

12th sq root
10.69516372 = 1 + m
9.69516372 = m


supposed to be 0.003961

There's no such thing as a "12th sq root". You raised the left side to the 12th power. That's different from taking the 12th root, which is the same as the 1/12 th power.

1.048576 = (1+m)^12
(1.048576)^(1/12) = 1+m
 
Mark44 said:
There's no such thing as a "12th sq root". You raised the left side to the 12th power. That's different from taking the 12th root, which is the same as the 1/12 th power.

1.048576 = (1+m)^12
(1.048576)^(1/12) = 1+m


finally! great, thanks for the help.
 
  • #10
Mark44 said:
There's no such thing as a "12th sq root".
A very good point. Unfortunately, even the "LaTex" used on this board requires that we enter a "12th root" as \sqrt[12]{x} !

You raised the left side to the 12th power. That's different from taking the 12th root, which is the same as the 1/12 th power.

1.048576 = (1+m)^12
(1.048576)^(1/12) = 1+m
 
  • #11
You can simplify things a bit by doing this:

[tex]1.024^2 = (1 + m)^{12}[/tex]

[tex]\left( 1.024^2 \right) ^{1/12} = \left[ (1 + m)^{12} \right]^{1/12}[/tex]

[tex]1.024^{1/6} = 1 + m[/tex]

[tex]\sqrt[6]{1.024} = 1 + m[/tex]

[tex]m = \sqrt[6]{1.024} - 1[/tex]
At least it keeps the numbers nice and tidy until the end!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K