Simple, but confusing question about Newton's laws

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To determine the tension in the string while a human on a sled is being pulled, the normal force depends on the system considered. If analyzing just the human, the normal force is the sled's force on the human; if considering both the human and sled, it’s the force from the Earth on the sled. Newton's laws are not applicable when the relative body is accelerating, complicating the calculation. For stacked objects, multiple normal forces exist, and a free body diagram for each object can clarify the forces at play. The net vertical force must equal zero if there is no vertical acceleration, leading to increased normal force magnitudes as one moves lower in the stack.
AznBoi
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Ok, if you need to determine a tension in a string that is being pulled by a human that is on a sled (the sled is accelerating outwards). Is the normal force the two weights combined??

I have Friction force + (- Tension)= ma

But for the friction force I don't know whether or not I need to find the human's normal force or the sled or both.

The human isn't moving, the sled is pulling away ---> but he is holding onto a string attatched to a wall

l------O The O is the human and he is standing on the sled.

Thanks!
 
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AznBoi said:
Ok, if you need to determine a tension in a string that is being pulled by a human that is on a sled (the sled is accelerating outwards). Is the normal force the two weights combined??

I have Friction force + (- Tension)= ma

But for the friction force I don't know whether or not I need to find the human's normal force or the sled or both.

The human isn't moving, the sled is pulling away ---> but he is holding onto a string attatched to a wall

l------O The O is the human and he is standing on the sled.

Thanks!
It depends what you're considering to be your system. If it's just the human, then the normal force is applied by the sled on the human. If the system is the sled and the human, then the normal force is the force applied by the Earth on the sled. Remember that Newton's laws don't apply when the relative body is itself accelerating.
 
So which one do I use? Do I add their weights together to get the normal force? Only the human is holding onto the string, but he is not moving. The sled is accelerating from below him, he is standing on the sled and resisting the motion because he is holding the string. =/
 
AznBoi said:
So which one do I use? Do I add their weights together to get the normal force? Only the human is holding onto the string, but he is not moving. The sled is accelerating from below him, he is standing on the sled and resisting the motion because he is holding the string. =/
For stacked objects in general there are multiple normal forces. Draw a free body diagram for each object in the stack. If there is no vertical acceleration, each object must have zero net force in the vertical direction. As you move lower in the stack, the normal force magnitudes will increase.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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