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Simple Complex Analysis Clarification

  1. Jun 23, 2015 #1

    RJLiberator

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    I am currently learning how to work with Cauchy-Riemann equations.

    The equation is f(z) = 2x+ixy^2.

    My question: is u(x,y) = 2x or just x?
    At this link: http://www.math.mun.ca/~mkondra/coan/as3a.pdf in letter e) they say u(x,y) is equal to x. But I don't understand how that is possible.

    Is that a typo or am I missing something critically important?

    Thank you.
     
  2. jcsd
  3. Jun 23, 2015 #2

    WWGD

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    I am 99.999997% that this should be ##u(x,y)=2x ## . It is a typo; Given f(x,y)=u(x,y)+iv(x,y), u(x,y) is the Real part of f(x,y)..
     
  4. Jun 23, 2015 #3

    RJLiberator

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    Excellent. Thank you for that confirmation.
     
  5. Jul 7, 2015 #4

    HallsofIvy

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    I presume that you text has already defined x and y as the real and imaginary parts of z, z= x+ iy, so that x and y are real numbers themselves.
     
  6. Jul 7, 2015 #5

    RJLiberator

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    Yes, that is correct indeed.
     
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