- #1
renedox
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"Simple" differentiation question
There is a question which is as follows:
(4^x)/(ln4)
I have tried many times to get the answer but with no success, would someone be so kind as to show me how to do it?
The answer is:
4^x
My working is as follows:
f(x) = (4^x)/(ln4)
F'(x) = ((ln 4 * ln 4 * 4^x) - (4^x - (1/4))) / ((ln 4)^2)
f'(x) = (4^x) - ((4^x * (1/4)) / ((ln 4)^2))
...help?
There is a question which is as follows:
(4^x)/(ln4)
I have tried many times to get the answer but with no success, would someone be so kind as to show me how to do it?
The answer is:
4^x
My working is as follows:
f(x) = (4^x)/(ln4)
F'(x) = ((ln 4 * ln 4 * 4^x) - (4^x - (1/4))) / ((ln 4)^2)
f'(x) = (4^x) - ((4^x * (1/4)) / ((ln 4)^2))
...help?