# Simple electronic energy level question

## Homework Statement

A certain laser outputs pure green light (photon energy 2.5 eV) with power 500 milliwatts (0.5 watts). How many photons per second does this laser emit?

## Homework Equations

not exactly sure, I know that Watts are equal to Jouls/sec
and that the electronic energy of a hydrogen atom is -13.6eV/N^2

## The Attempt at a Solution

can someone run through this with me and give me a good explanation? do i convert .5 watts to eV and then divide that number by 2.5 eV?

3.121e+18(eV)/2.5 = 2.348e18?

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Hiya! You're almost there m8 but one thing you gotta remeber is that 1eV is equal to 1.6E-19 joules. so 2.5eV is what?? And then youre virtually there, because your right and watts are J/s and that thing is emitting 0.5 J/s.
Ha and just realised because i didnt check your first method is perfect however i dont know what you did because 3.121/2.5 does not equal 2.348! To avoid all the decimals though its MUCH easier to convert the 2.5eV to joules first. You get lovely round numbers then.

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i dont understand this conceptually though, here is my new try with units, but i get a stupid answer at the end?

(1photon/2.5eV)*(.5*8e-20eV/s) = 3.2e-20 photons/second
but that can't possibley be correct

what did i flip or do wrong?

Hmm i dont understand your method at all ha! There should be no eV/s it should be in J/s.

OK here goes ill try and explain it, try and do it my way cuz i think its more intuitive :). Watts = the amount of joules evolved per second. First part to realise which you got. Secondly 1eV=1.6E-19 joules of energy. How many eV of energy does one photon have in this case?? 2.5eV! SO therefore the amount of energy in joules that one photon has in this case is 2.5*1.6E-19. That will be a MINISCULE amount like E-19. NOW this laser thing is pumping out 0.5 joules per second. How many photons is in that amount of energy?? Just divide 0.5 joules by that number you get for the energy of a photon. And youve got the number per second.

Now REMEMBER this because it is so cool and once you get good at it you can bomb through these questions like nothing. Look at the units of the thing your loking at. In this case we want s^-1 because its photons PER SECOND. We do not want joules so cancel out the joules while keeping s^-1. So like this watts are Js^-1, eV are in J we just did watts/eV which =(Js^-1)/J, oh and look we cancelled out the J and are left with s^-1(aka per second). Trying to get to the right units at the end will almost always work. If you look at your attempt it ends up with J^-1 s^2 as its units, that aint gonna give us the answer.