Simple gravitational potential energy

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SUMMARY

The gravitational potential energy (Ug) of a 400-N child on a swing with 2.00 m ropes at a 30.0° angle from the vertical is calculated using the formula Ug = mgy. The correct height (y) is derived from the vertical displacement, which is determined by the expression 2m(1 - cos(30°)). This results in a potential energy of 107 Joules. The confusion arises from understanding the vertical height change, which is essential for accurate potential energy calculations.

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  • Knowledge of basic physics equations related to energy
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sireh
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Homework Statement


A 400-N child is in a swing that is attached to a pair of ropes 2.00 m long. Find the gravitational potential energy of the child-Earth system relative to the child’s lowest position when

(b) the ropes make a 30.0° angle with the vertical

Homework Equations


Ug=mgy

The Attempt at a Solution


b.) Ug = 400N ⋅ 2m(1-cos30)
Ug = 107J

I understand everything about the problem (and was able to do the other parts of it without issue) except where the 1-cos30 comes from. Even drawing it out I just can't visualize where that is coming from. I originally thought that it would just be 2m(cos30) but the answer key says that is wrong.
 
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sireh said:
I understand everything about the problem (and was able to do the other parts of it without issue) except where the 1-cos30 comes from. Even drawing it out I just can't visualize where that is coming from. I originally thought that it would just be 2m(cos30) but the answer key says that is wrong.

i think the potential energy change is initial state when it was at the lowest point and then it was raised to an angle 30 degree- so the the child was raised to certain height and that height matters for P.E. calculation -i.e. your y... so making some triangle with original position and raised position calculate y -the amount of vertical distance raised to be multiplied to the load raised...
 
How much higher is the 30 degree point than the bottom point?
 

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