Simple harmonic motion calculations from doubling the mass.

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SUMMARY

The discussion focuses on calculating the new amplitude, maximum velocity, and maximum acceleration of a simple harmonic oscillator when the mass is doubled. Given an initial amplitude of 0.117m, a mass of 0.1kg, and a spring constant of 3.587N/m, the new amplitude is determined to be 0.234m after doubling the mass. The maximum acceleration calculated is 4.19679m/s². The relationship between mass and velocity is clarified using the equation v_max = A√(k/m), indicating that doubling the mass affects the maximum velocity.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with Hooke's Law and spring constants
  • Knowledge of basic calculus and algebra for solving equations
  • Ability to manipulate and interpret physical formulas
NEXT STEPS
  • Study the derivation of the equations for simple harmonic motion
  • Learn about the effects of mass changes on oscillatory systems
  • Explore energy conservation in simple harmonic motion
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Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators seeking to enhance their understanding of simple harmonic motion calculations.

Wes Ellgass
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Homework Statement


What will the new amplitude be if A=.117m and the mass is 0.1kg. The spring constant is 3.587N/m
and the mass is then doubled.
What is the new velocity max?
What is the acceleration max?

Homework Equations


Fnet= -kx, vmax=A(ω), ω= √k/m

The Attempt at a Solution


0.117m=.1kg(a)/(3.587N/m)
a=4.19679m/s2
A=4.197(.2kg)/3.587N/m)= 0.234m
 
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Welcome to PF;
Did you have a question?
In general we can check your reasoning - but you have to explain your reasoning.
Some people will, very occasionally, check your algebra and even more rarely your arithmetic.
However, we cannot usually tell you if you are right or wrong because that usually amounts to doing your homework for you.

there's a way to see if the calculation works - this is by understanding the equations:
ie. ##v_m = A\sqrt{k/m}## so if you double the ##m##, what happens to ##v_m## - in general?
 

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