# Simple harmonic motion calculations from doubling the mass.

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1. Oct 8, 2016

### Wes Ellgass

1. The problem statement, all variables and given/known data
What will the new amplitude be if A=.117m and the mass is 0.1kg. The spring constant is 3.587N/m
and the mass is then doubled.
What is the new velocity max?
What is the acceleration max?
2. Relevant equations
Fnet= -kx, vmax=A(ω), ω= √k/m

3. The attempt at a solution
0.117m=.1kg(a)/(3.587N/m)
a=4.19679m/s2
A=4.197(.2kg)/3.587N/m)= 0.234m

2. Oct 9, 2016

### Simon Bridge

Welcome to PF;
Did you have a question?
In general we can check your reasoning - but you have to explain your reasoning.
Some people will, very occasionally, check your algebra and even more rarely your arithmetic.
However, we cannot usually tell you if you are right or wrong because that usually amounts to doing your homework for you.

Theres a way to see if the calculation works - this is by understanding the equations:
ie. $v_m = A\sqrt{k/m}$ so if you double the $m$, what happens to $v_m$ - in general?