A block with mass m =6.6 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.26 m. While at this equilibrium position, the mass is then given an initial push downward at v = 4.4 m/s. The block oscillates on the spring without friction.
at time 0.39 s what is the speed of the block
The Attempt at a Solution
i sub A= 0.716681695
t= 0.39 into the equation and get 2.990262698
my calculator is on rads and i really dont understand what is going wrong in this calculation i found the other variables using the given values