Simple Harmonic Motion - Getting Acceleration from Velocity

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SUMMARY

This discussion focuses on calculating acceleration from velocity in Simple Harmonic Motion (SHM) for a speaker driven by a known voltage and frequency. The user correctly identifies the equations for SHM, including x = Asin(wt), x' = wAcos(wt), and x'' = -w^2Asin(wt). The user seeks clarification on the amplitude required for their calculations, questioning whether it should be based on the voltage or the displacement of the speaker, which remains unknown. The relationship between sine and cosine functions is also highlighted, emphasizing their phase difference in SHM.

PREREQUISITES
  • Understanding of Simple Harmonic Motion (SHM) principles
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of angular frequency (w = 2πf)
  • Basic physics concepts related to force and acceleration
NEXT STEPS
  • Research the concept of amplitude in SHM and its significance
  • Learn about the relationship between voltage, frequency, and displacement in speakers
  • Explore the derivation and application of acceleration equations in SHM
  • Examine graphical representations of sine and cosine functions in SHM
USEFUL FOR

Students and educators in physics, particularly those studying mechanics and wave motion, as well as engineers working with audio systems and speaker design.

jasonian
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Homework Statement


I am doing an experiment where I am measuring the force a speaker is exerting when it is driven by a certain voltage and frequency, so my voltage and frequency values are known. I am assuming the speaker is undergoing SHM and I am measuring its peak to peak velocity.

Homework Equations


I understand that for SHM:

x = Asin(wt)
x' = wAcos(wt)
x'' = -w^2Asin(wt)

The Attempt at a Solution


Now, because I am measuring the peak to peak velocity, is it correct to say cos(wt) and sin(wt) are equal and therefore x'' = -w*x', where w = 2*pi*f and x' = my peak to peak velocity measurements divided by 2.

Furthermore, if I were not to take this approach my acceleration equation would be x'' = -w^2Asin(wt).
Where,

w = 2*pi*f
t = period of 1 cycle
A = (?)

I am not quite sure what the amplitude would be in my situation. What kind of amplitude is required? The amplitude of the voltage driving the speaker? Or the amplitude of the displacement of the speaker? (Which in this case is unknown as only the velocity measurements are taken).

Any help is appreciated. Thanks.
 
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jasonian said:

Homework Statement


I am doing an experiment where I am measuring the force a speaker is exerting when it is driven by a certain voltage and frequency, so my voltage and frequency values are known. I am assuming the speaker is undergoing SHM and I am measuring its peak to peak velocity.

Homework Equations


I understand that for SHM:

x = Asin(wt)
x' = wAcos(wt)
x'' = -w^2Asin(wt)

The Attempt at a Solution


Now, because I am measuring the peak to peak velocity, is it correct to say cos(wt) and sin(wt) are equal and therefore x'' = -w*x', where w = 2*pi*f and x' = my peak to peak velocity measurements divided by 2.

Furthermore, if I were not to take this approach my acceleration equation would be x'' = -w^2Asin(wt).
Where,

w = 2*pi*f
t = period of 1 cycle
A = (?)

I am not quite sure what the amplitude would be in my situation. What kind of amplitude is required? The amplitude of the voltage driving the speaker? Or the amplitude of the displacement of the speaker? (Which in this case is unknown as only the velocity measurements are taken).

Any help is appreciated. Thanks.

Look at graphs of ##\sin(\theta)## and ##\cos(\theta)##; you will see that where one of them is at a peak the other is half-way between a peak and a through; that is, when ##\sin(\theta) = \pm 1## we have ##\cos(\theta) = 0##, and vice-versa. You can also see this without drawing a graph if you remember that ##\sin^2(\theta) + \cos^2(\theta) = 1## for all angles ##\theta##.
 

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