Simple Harmonic Motion of a Mass Hanging from a Vertical Spring

AI Thread Summary
In the discussion on simple harmonic motion of a mass hanging from a vertical spring, the initial equation set up to relate gravitational potential energy and elastic potential energy is critiqued. The participant calculated displacement using the formula x=(2mg)/k but received incorrect results. Key points raised include the clarification that elastic potential energy (EPE) does not decrease as the mass descends, and that forces acting on the mass at rest must be considered. The conversation emphasizes that conservation of mechanical work does not imply equal losses in potential energies, but rather that work lost in one form is gained in another. The misunderstanding of energy conservation principles in this context is central to the confusion.
momoneedsphysicshelp
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Homework Statement
A 13.6 kg mass is placed on a vertically hanging spring (k=8.8). The mass is slowly released so it comes to rest. What is the displacement from the natural length of the spring?
Relevant Equations
Gravitational potential energy = m*g*x
Elastic potential energy = (1/2)kx^2
Assuming zero spring mass and zero friction,
At the greatest value of x, the loss in gravitational potential energy should equal the loss in elastic potential energy.

so I did

(1/2)kx^2=mgx

to isolate x in the formula,

x=(2mg)/k

then I plugged in my values so:

(2*13.6*9.81)/8.8= 30.3218

so the displacement is 30.32 m.

Can anyone please check what mistake I made in this problem, when I submit it, it is incorrect.
 
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momoneedsphysicshelp said:
At the greatest value of x, the loss in gravitational potential energy should equal the loss in elastic potential energy.
You mean the gain in EPE, but this scenario does not conserve work:
"The mass is slowly released"
 
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haruspex said:
You mean the gain in EPE, but this scenario does not conserve work:
"The mass is slowly released"
How come elastic potential energy will not decrease as the mass goes down?
 
It's slowly released until it comes to rest.

What can you say about the forces acting on it at this point, at rest?
 
rsk said:
It's slowly released until it comes to rest.

What can you say about the forces acting on it at this point, at rest?
decreasing gravitational potential energy
 
Forces, not energy. What can you say about the forces on an object which is at rest?
 
momoneedsphysicshelp said:
How come elastic potential energy will not decrease as the mass goes down?
Elastic potential energy of a spring is at minimum when the spring is relaxed. Compressing or stretching it increases the EPE according to ½kx2, where x is the change in length from the relaxed length.

Conservation of mechanical work means that work lost by one aspect (potential or kinetic) is gained by other aspects. There is no law that says the loss in one should equal the loss in another,
 

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