(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A hanging spring stretches by 35.0cm when an object of mass 450g is hung on it at rest. In this situation we define its position as x=0. The object is pulled down an additional 18.0cm and released from rest to oscillate without friction. What is its position x at a moment 84.4s later?

2. Relevant equations

x(t)= Acos([tex]\omega[/tex]t+[tex]\Phi[/tex])

[tex]\omega[/tex]=[tex]\sqrt{\frac{k}{m}}[/tex]

3. The attempt at a solution

I know that I need to use these two equations, but I don't know k. So I was thinking that I need to use the information that a 450g weight stretches the spring 35.0cm to find the spring constant k. I just wasn't sure how to do that. I was thinking I should just multiply 450 by 35 and divide by 9.8 because it is hanging, but this didn't work for me.

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# Homework Help: Simple Harmonic Motion of a spring

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