A u-tube manometer is half filled with water. The liquid levels are displaced so that one side is higher than the other. The water is then left free to oscillate from side to side. The tube has a cross sectional area of 1.cm^2 and the inital displacement is 0.1m from the rest position, which is 0.5m above the middle of the bottom of the tube. The total length of tube filled with water is 1.1m. g = 10 N/kg 1) Using the relationship of pressure and density and depth, calculate the pressure at the bottom of the tube due to each of the unbalanced columns of water and hence the resultatn force acting.. Please someone explain/help.