Simple harmonic motion questions

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Homework Help Overview

The discussion revolves around two problems related to simple harmonic motion and forces. The first problem involves a u-tube manometer filled with water and the calculation of pressure and force due to unbalanced columns of water. The second problem pertains to a bungee jumper and the analysis of the bungee cord's tension and extension during the jump.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between pressure, force, and area in the context of the manometer. Questions arise about calculating force from pressure and the implications of the bungee jumper's mass and the bungee's properties on tension and extension.

Discussion Status

Some participants have successfully calculated pressures and are discussing the method to find force. Others are questioning the tension in the bungee cord and comparing their calculations with provided answers, indicating a productive exchange of ideas without a clear consensus on the tension values.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the information they can share or the methods they can use. There is an emphasis on understanding the principles of conservation of energy and the relationships between forces in the context of oscillatory motion.

blackcat
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A u-tube manometer is half filled with water. The liquid levels are displaced so that one side is higher than the other. The water is then left free to oscillate from side to side. The tube has a cross sectional area of 1.cm^2 and the inital displacement is 0.1m from the rest position, which is 0.5m above the middle of the bottom of the tube.

The total length of tube filled with water is 1.1m.

g = 10 N/kg

1) Using the relationship of pressure and density and depth, calculate the pressure at the bottom of the tube due to each of the unbalanced columns of water and hence the resultatn force acting..

Please someone explain/help.
 
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the answers are meant to be "4000Pa, 6000Pa, 0.2N"
 
Never Mind I Got It..
 
Well I got the pressures. How can I work out the force?
 
don't you just use p = F/area?
 
yeah that's it thanks.

also:

a bungee jumper jumps from a high platform. he has a mass of 60kg and the rope, which is tied to the platform is light, 20m long and perfectly elastic with a stiness of 30 N/m.

g = 10N/kg

How far will the bungee have stretched when the jumper first comes to rest?
 
HINT: Conservation of energy.
 
thanks i will have a look
 
thanks for the help.

how do I find out the tension in the bungee when he's at rest? i'd have thought it's T = mg = 600N, but the answer says it's 1600N.
 
  • #10
blackcat said:
thanks for the help.

how do I find out the tension in the bungee when he's at rest? i'd have thought it's T = mg = 600N, but the answer says it's 1600N.
No problem. What is the extension in the bungee at this point (lowest point)?
 

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