1. The problem statement, all variables and given/known data A particle moves along the x axis. It is initially at the position 0.250 m, moving with velocity 0.200 m/s and acceleration -0.290 m/s2. Suppose it moves with constant acceleration for 5.80 s. Position of Particle after 5.80 Seconds - -3.4678 m. Velocity of Particle After 5.80 Seconds -1.482 m/s Next, assume it moves with simple harmonic motion for 5.80 s and x = 0 is its equilibrium position. What is its position at the end of this time interval? What is its velocity at the end of this time interval? 2. Relevant equations Attempts : I attempted to use the formula X(t)= A cos (wt), with A being the amplitude 0.250 (because a spring can't stretch farther than its intial position) and w = angular velocity which I used 0.2 / .25. For the velocity I used the formula- v(t)=w A sin (t) From this point I was completely lost because I could not find a way to incorporate the constant acceleration. Simple Harmonic Motion equations if you could leave an explanation, it's be greatly appreciated!!