Simple Harmonic Motion + Regular Kinematics

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fnaarfnaar
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Homework Statement


A particle moves along the x axis. It is initially at the position 0.250 m,
moving with velocity 0.200 m/s and
acceleration -0.290 m/s2.
Suppose it moves with constant acceleration for 5.80 s.

Position of Particle after 5.80 Seconds - -3.4678 m.
Velocity of Particle After 5.80 Seconds -1.482 m/s

Next, assume it moves with simple harmonic motion for 5.80 s and x = 0 is its equilibrium position.

What is its position at the end of this time interval?
What is its velocity at the end of this time interval?

Homework Equations

Attempts :

I attempted to use the formula X(t)= A cos (wt), with A being the amplitude 0.250 (because a spring can't stretch farther than its intial position) and w = angular velocity which I used 0.2 / .25.

For the velocity I used the formula- v(t)=w A sin (t)

From this point I was completely lost because I could not find a way to incorporate the constant acceleration. Simple Harmonic Motion equations

if you could leave an explanation, it's be greatly appreciated!
 
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fnaarfnaar said:

Homework Statement


A particle moves along the x axis. It is initially at the position 0.250 m,
moving with velocity 0.200 m/s and
acceleration -0.290 m/s2.
Suppose it moves with constant acceleration for 5.80 s.

Position of Particle after 5.80 Seconds - -3.4678 m.
Velocity of Particle After 5.80 Seconds -1.482 m/s

Next, assume it moves with simple harmonic motion for 5.80 s and x = 0 is its equilibrium position.

What is its position at the end of this time interval?
What is its velocity at the end of this time interval?


Homework Equations



Simple Harmonic Motion equations

if you could leave an explanation, it's be greatly appreciated!
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