Simple Harmonic Motion - seemingly easy yet

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Homework Help Overview

The discussion revolves around a problem related to simple harmonic motion, specifically involving the calculation of displacement using the function x = (2.0 m) cos[(2pi rad/s)t + pi/2 rad] at t = 4.0 s. Participants are exploring the implications of plugging values into the equation and the behavior of the cosine function.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method of substituting time into the equation to find displacement, with some questioning the correctness of their calculations and the role of the cosine function at certain angles.

Discussion Status

There is an ongoing exploration of the calculations involved, with some participants providing insights into potential mistakes and clarifying the behavior of the cosine function at specific angles. The discussion reflects a mix of attempts to understand the problem and corrections regarding assumptions made in the calculations.

Contextual Notes

Participants note confusion regarding the output from a calculator and the expected results from the equation, highlighting the importance of understanding the periodic nature of trigonometric functions in the context of simple harmonic motion.

Shadow Cloud
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The function x = (2.0 m) cos[(2pi rad/s)t + pi/2 rad] gives the simple harmonic motion of a body. Find the following values at t = 4.0 s.
(a) the displacement: ____m
Correct me if I am wrong, but to get x all I have to do is just plug 4.0 s in for t in that equation mentioned above right? I set my calculator to radians and did what I just said and get 6E^-13, but for some reason webassign (website where I answer the problem at) says I'm wrong. What gives?
 
Last edited:
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Shadow Cloud said:
Correct me if I am wrong, but to get x all I have to do is just plug 4.0 s in for t in that equation mentioned above right?
That's all there is to it.
I set my calculator to radians and did what I just said and get 6E^-13, but for some reason webassign (website where I answer the problem at) says I'm wrong.
You made a mistake. What angle (in radians) are you taking the cosine of?
 
Oh I'm sorry, I forgot to include the pi in the equation.
 
So I assume you corrected your mistake?
 
Oh I haven't, I just forgot to include it when I posted the problem. I still do not understand why I am not getting the right answer when all I have to do is plug in 4.0 for T.
 
I think if you just take a look at the trigonometric function itself, it should be no surprise to you that any integer value of t will result in the cosine function returning 0.
 
Shadow Cloud said:
I still do not understand why I am not getting the right answer when all I have to do is plug in 4.0 for T.
mezarashi explained it, but your real mistake is using a calculator to solve this. :smile: If you just looked at the equation, you'd see that plugging in T = 4 sec gives you an angle of pi/2 radians. What's the cosine of pi/2 radians (or 90 degrees)? (Note that 8 1/2 pi radians is equivalent to pi/2 radians since the trig functions are periodic over 2 pi radians.)

Your calculator answer was "correct": 6E^-13 is pretty close to zero! (Round it off.)
 
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And pi/2 for cos is 0...yes you're right, the calculator did mess me up in this case. Thank you for the help.
 

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