Simple harmonic motion velocity and acceleration

Click For Summary
SUMMARY

The discussion centers on calculating the frequency, mass, and amplitude of a block attached to a spring with a spring constant of 125 N/m, given its position (0.800 m), velocity (-11.3 m/s), and acceleration (-119 m/s²). The angular frequency is derived from the relationship ω² = k/m, where k is the spring constant. The amplitude is calculated using the equation K = Ma/A, resulting in an amplitude of 0.8 m. The forum participants also discuss the behavior of acceleration and velocity at maximum displacement.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with Hooke's Law and spring constants
  • Knowledge of angular frequency and its calculations
  • Ability to manipulate equations involving displacement, velocity, and acceleration
NEXT STEPS
  • Study the derivation of angular frequency in simple harmonic motion
  • Learn how to apply Hooke's Law in various oscillatory systems
  • Explore the relationship between amplitude, velocity, and acceleration in oscillations
  • Investigate the effects of mass on the frequency of oscillation
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts of simple harmonic motion.

alexandertg6
Messages
3
Reaction score
0

Homework Statement



An oscillator consists of a block attached to a spring (k = 125 N/m). At some time t, the position (measured from the system's equilibrium location), velocity, and acceleration of the block are x = 0.800 m, v = -11.3 m/s, and a = -119 m/s2

(a) calculate the frequency of oscillation (Hz)

(b) calculate mass of block (kg)

(c) calculate the amplitude of motion (m)

Homework Equations


v(t) = -angular frequency(displacement)sin(phase)
a(t) = - angular frequency^2(displacement)cos(phase)
phase = angular frequency(t) + phase angle


The Attempt at a Solution



-11.3 = -angular frequency (.8) sin (angular frequency x t + phase angle) but i have 3 variables

i feel like there is some simple and fairly easy way to do this... i just don't know what it is

thank you for the help

Alex
 
Physics news on Phys.org
So isn't

a(t) = - ω2*x(t)

and since F = m*a = -k*x then substituting for a ...

ω2 = k/m
 
thank you very much that was quite helpful, but I am having some problems with the amplitude calculation...

i found the equation K = Ma/A where A is amplitude but that just gives me the original displacement

125 = (.84 x -119)/ A

A = .8

any ideas?
 
What will the acceleration and velocity be when the bob is at a maximum displacement?
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
3
Views
844
Replies
16
Views
2K
  • · Replies 51 ·
2
Replies
51
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 15 ·
Replies
15
Views
6K
Replies
9
Views
2K