1. The problem statement, all variables and given/known data The velocity of an object in simple harmonic motion is given by v(t)= -(0.347 m/s)sin(15.0t + 2.00π), where t is in seconds. What is the first time after t=0.00 s at which the velocity is -0.100 m/s? 2. Relevant equations 3. The attempt at a solution -0.1 = -(0.347)sin(15t + 2[tex]\pi[/tex]) 0.2882 = sin(15t + 2[tex]\pi[/tex]) 15t = arcsin(0.2882) - 2[tex]\pi[/tex] t = -0.39939 s - its a neg time so i thought just adding 2[tex]\pi[/tex] would take me to the same point on graph but the positive side : 0.4284 s <-- still the wrong answer so im not too sure where im going wrong.. maybe its just my algebra or is it the whole approach to the question? thanks!