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Homework Statement
The velocity of an object in simple harmonic motion is given by v(t)= -(0.347 m/s)sin(15.0t + 2.00π), where t is in seconds. What is the first time after t=0.00 s at which the velocity is -0.100 m/s?
Homework Equations
The Attempt at a Solution
-0.1 = -(0.347)sin(15t + 2[tex]\pi[/tex])
0.2882 = sin(15t + 2[tex]\pi[/tex])
15t = arcsin(0.2882) - 2[tex]\pi[/tex]
t = -0.39939 s
- its a neg time so i thought just adding 2[tex]\pi[/tex] would take me to the same point on graph but the positive side : 0.4284 s <-- still the wrong answer
so I am not too sure where I am going wrong.. maybe its just my algebra or is it the whole approach to the question?
thanks!