Simple Harmonics - Kind of wierd

  • Thread starter Thread starter kevinr
  • Start date Start date
  • Tags Tags
    Harmonics
Click For Summary

Homework Help Overview

The discussion revolves around a problem involving simple harmonic motion, specifically analyzing the position of a mass on a spring as described by a cosine function of time. The original poster presents an equation for displacement and seeks to find the position at a specific time.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to substitute a value for time into the position equation to find the corresponding position. Some participants question whether the equation was derived or provided, and whether the calculations were performed in the correct mode (degrees vs. radians).

Discussion Status

The discussion is ongoing, with participants exploring the implications of using different units for trigonometric functions. There is a recognition that the original poster's approach was correct in principle, but there is a suggestion to verify the mode of calculation.

Contextual Notes

The original problem statement was provided in full, and the original poster asserts that all given information is correct. There is a focus on ensuring the proper use of radians for the calculations involved.

kevinr
Messages
32
Reaction score
0
[SOLVED] Simple Harmonics - Kind of weird

Homework Statement



Question:
A 1.30 kg mass on a spring has displacement as a function of time given by the equation:

[tex]x\left( t \right) = \left( {7.40\;{\rm{ cm}}} \right)\,\cos\:\left[ {\left( {4.16\;{\rm{ s}}^{ - 1} } \right)t - 2.42} \right].[/tex]

Find the position of the mass at t = 1.00s.

Homework Equations



?

The Attempt at a Solution



Ok so since this is a position equation, i figured that i would just plugin 1 for t and get the answer. But that seems to be wrong and i can't figure out why. (i did change 7.4 cm to m).

I figured out other parts for this equation to be:
T = 1.51s
k = 22.5 N/m
Vmax = .308 m/s
Fmax = 1.67 N

Any help would be great!

Thanks!
 
Physics news on Phys.org
Hello,

Well, if you have a position equation that is only a function of time, then yes, you should be able to plug in the time and get the position.

So

Is this an equation that was given to you, or is this an equation you derived from the problem? You may have made a mistake in an earlier step. What exactly did the original problem say?
 
Its an equation given to me.

Problem said exactly what i posted. Everything was given to me and everything is correct.

When i solve this: i get .073965879

Can anyone confirm this? I tried that and it was wrong. (my calculator is in degrees mode - i think that's right)
 
Hello,

Well, I get the same number in degrees mode, but you probably want to be working in radians, as this is the unit typically used for these types of things. Try radians.

What answer are you looking to get?
 
O ok it works in radians.

Thanks!
 

Similar threads

Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 12 ·
Replies
12
Views
10K
  • · Replies 1 ·
Replies
1
Views
3K